tag:blogger.com,1999:blog-26812847.post6378917935419965976..comments2024-03-28T11:20:40.874+01:00Comments on Problemas de Ajedrez | Chess Problems: Problema de ajedrez 1951: Estudio de Louis van Vliet (Deutsche Schachzeitung, 1888)JLPMhttp://www.blogger.com/profile/00891045835734721638noreply@blogger.comBlogger5125tag:blogger.com,1999:blog-26812847.post-58538061230691418432021-03-29T11:43:05.819+02:002021-03-29T11:43:05.819+02:00Gracias Joaquim por tu apunte. Me congratula ver s...Gracias Joaquim por tu apunte. Me congratula ver solucionistas que dan la solución en inglés. <br /><br />La solución completa de este estudio sería:<br /><br /><b>1.Db4! Dh1!</b><br /><br />Si 1...Dd5 o Df3 sigue 2.Da4+ Rb6 3.Db3+! Dxb3 4.b8D+ ganando.<br /><br />Si 1...Dg2 2.Da3+ Rb6 3.Db2+! Dxb2 4.b8D+ ganando.<br /><br /><b>2.Da3+ Rb6</b><br /><br />Si 2...Rb5 3.Db2+ Rc4 (3...Ra4 4.Da2+ Rb4 5.Db1+ Dxb1 6.b8D+ ganando) 4.Ra7 Dg1+ (4...Dh7 5.Ra6 Dg6+ 6.Db6 ganando) 5.Ra6 Dg6+ 6.Db6 ganando.<br /><br /><b>3.Db2+ Rc7</b><br /><br />Si 3...Ra6 4.Da2+ Rb6 5.Db1+ Dxb1 6.b8D+ ganando.<br /><br />Si 3...Rc5 4.Ra7 Dh7 5.Db6+ Rc4 6.Ra6 ganando.<br /><br />Si 3...Rc6 4.b8D ganando.<br /><br /><b>4.Dh2+! Dxh2<br />5.b8D+</b><br /><br />Y las blancas ganan.<br />JLPMhttps://www.blogger.com/profile/00891045835734721638noreply@blogger.comtag:blogger.com,1999:blog-26812847.post-15788943025655192762021-03-17T17:26:59.551+01:002021-03-17T17:26:59.551+01:00José Luis: Creo que por lo menos existe otro final...José Luis: Creo que por lo menos existe otro final de este compositor:<br />8/8/3p4/4p3/4P3/5B2/7p/4K1k1 w - - 0 1 ...<br />... aunque la solución parece fácil.<br />Fue publicado en Deutsche Schachzeitung en 1895Joaquimhttps://www.blogger.com/profile/17590920091941302468noreply@blogger.comtag:blogger.com,1999:blog-26812847.post-58062354556846570712021-03-16T16:09:18.581+01:002021-03-16T16:09:18.581+01:00Efectivamente es lo mejor: 1.Db4!... Una continuac...Efectivamente es lo mejor: 1.Db4!... Una continuación 1...Dh1 2.Da3+ Rb5 3.Db2+ Ra6 (Rc4) 4.Da2+ Rb5 5.Db1+ Dxb1 6.b8D+ Rc6 (Ra4) 7.Dxb1... 1-0<br /><br />ESOTOhttps://www.blogger.com/profile/13187786381053793747noreply@blogger.comtag:blogger.com,1999:blog-26812847.post-69888995600591714192021-03-16T15:46:15.881+01:002021-03-16T15:46:15.881+01:00I think I'll go on, because I think I've g...I think I'll go on, because I think I've got something:<br />1) Qb4 ...<br />If black moves 1) ... Qd5 <br /> 2) Qa4+ Kb6 (only one in order not to trade queens)<br /> 3) Qb3+ (forking the black queen and forcing the take)<br /> 3) ... Qxb3 <br /> 4) b8=Q+ <br />This applies for every square the black queen takes (d5,e4,f3,g2 and h1) in order to keep the diagonal, and the solution is the same, to bring the king into the b column and forking the queen in order to force the take and then promote. I hope I got it right! My name is Jorge. <br />Anonymoushttps://www.blogger.com/profile/10860275047577412119noreply@blogger.comtag:blogger.com,1999:blog-26812847.post-90048012923585941442021-03-16T15:19:56.686+01:002021-03-16T15:19:56.686+01:00This is my first time commenting on this blog, and...This is my first time commenting on this blog, and im not as wise as everybody here, but I'll give it a try and say the black queen needs to lose control of the diagonal in order for the pawn to promote. Moving 1.- Qb4 I think its a good way to start maybe?Anonymoushttps://www.blogger.com/profile/10860275047577412119noreply@blogger.com